This function should remove the vowels in string and return string without vowels
function removeVowels(string) {
var newstring = '';
var vowels = ['a','e','i','o','u'];
for ( i in string) {
if ( i.toLowerCase() not in vowels) { // I know this is wrong but is anything I can use instead of "not in" in JS?
continue
} else {
newstring += i
}
}
return newstring;
}
JavaScript does not have a not keyword. Instead, it has a ! for whenever you want to use not.
JS's in is NOT the same as python's in. JS uses it for indexes, and if you want the character at the index, you should use of.
I have also made some minor tweaks here and there like not using var and removing the continue statements.
function removeVowels(string) {
// Instead of using var here, use let and const.
let newString = '';
const vowels = ['a','e','i','o','u'];
// Loop through every character of string
for (const char of string) {
// Instead of the continue that you used, you can just simply check if the vowels array includes the specific character.
if (!vowels.includes(char.toLowerCase())) {
// This just appends the character to the new string variable
newString += char;
}
}
return newString;
}
console.log(removeVowels('This string will not have any vowels in it.'));